Binary Number with Alternating Bits

逐位比较即可

class Solution(object):
    def hasAlternatingBits(self, n):
        """
        :type n: int
        :rtype: bool
        """
        n, cur = divmod(n, 2)
        while n:
            if cur == n % 2:
                return False
            n, cur = divmod(n, 2)
        return True